AREA OF TRIANGLE=A=

$ \frac{1}{2} $(base)(hight)

=\frac{1}{2}(b)(h)

Author- Tharanath
License- CC BY SA 4.0

a = 14 (slider from 0 to 20, step 0.5)
b = 6 (slider from 0 to 20, step 0.5)
A = (1, 2)
B = Point(Circle[A, a])
c = Segment(A, B)
C_1 = Point(c)
C = Point(Circle[C_1, b])
e = Segment(A, C)
f = Segment(B, C)
text4: "=\frac{1}{2}(" + (LaTeX[a]) + ")(" + (LaTeX[b]) + ")"
poly1, b_1, c_1, a_1 = Polygon(C, A, B)
text5: "=" + ((a * b / 2)) + " sq.units"