Angle sum of a triangle
Author: Radha

Move the points!

Demonstration.

किसी भी तरफ एक भुजा पे रेखा खींचें

when you move the line up to
 the 3rd vertex,you will observe 
3 adjacent angles whose 
sum will be equal to 180°
Now can we prove 
Angle sum property of a Triangle?

त्रिभुज की कोण योग गुण

लेखक- श्रीरंजनी, आईटी फॉर चेंज, बेंगलुरु 
लाइसेंस- क्रियेटिव कॉमन्स शेयर-अलाइक लाइसेंस

खिसकाएं = -0.5 (slider from -0.5 to 1.5, step 0.005)
d_1 = If(खिसकाएं < 0, 0, If[खिसकाएं < 1, खिसकाएं, 1])
C = (2.905601545782864, 5.91765899134235)
B = (4.824625072819469, 3.5656250274359573)
A = (1.5081587722485164, 3.5361015885584703)
poly1, c, a, b = Polygon(A, B, C)
AngleB = Angle(C, B, A)
AngleA = Angle(B, A, C)
AngleC = Angle(A, C, B)
f = Line(B + (d_1 * (C - B)), c)
D = Intersect(b, f)
E = Intersect(a, f)
e = Ray(B, C)
F = Point(e)
G = Point(f)
H = Point(f)
δ = Angle(F, E, G)
g = Ray(A, C)
I = Point(g)
ε = Angle(H, D, I)
h = Line(A, B)
ζ = Angle(I, C, F)
d = false
Sum: AngleA + AngleB + AngleC
text3: "" + (LaTeX[AngleA]) + "+" + (LaTeX[AngleB]) + "+" + (LaTeX[AngleC]) + "=" + (LaTeX[Sum]) + ""
α = Angle(A, C, B)
β = Angle(C, B, A)
γ = Angle(B, A, C)
text4: "कोण A+कोण B+कोण C=" + Sum + ""